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84 lines
2.7 KiB
84 lines
2.7 KiB
4 years ago
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#
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# ConvertAsm.py: Automatically generated from CopyMem.asm
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#
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#------------------------------------------------------------------------------
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#
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# Copyright (c) 2006 - 2018, Intel Corporation. All rights reserved.<BR>
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# This program and the accompanying materials
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# are licensed and made available under the terms and conditions of the BSD License
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# which accompanies this distribution. The full text of the license may be found at
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# http://opensource.org/licenses/bsd-license.php.
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#
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# THE PROGRAM IS DISTRIBUTED UNDER THE BSD LICENSE ON AN "AS IS" BASIS,
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# WITHOUT WARRANTIES OR REPRESENTATIONS OF ANY KIND, EITHER EXPRESS OR IMPLIED.
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#
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# Module Name:
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#
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# CopyMem.S
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#
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# Abstract:
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#
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# CopyMem function
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#
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# Notes:
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#
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#------------------------------------------------------------------------------
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#------------------------------------------------------------------------------
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# VOID *
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# EFIAPI
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# InternalMemCopyMem (
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# IN VOID *Destination,
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# IN VOID *Source,
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# IN UINTN Count
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# )
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#------------------------------------------------------------------------------
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ASM_GLOBAL ASM_PFX(InternalMemCopyMem)
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ASM_PFX(InternalMemCopyMem):
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pushq %rsi
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pushq %rdi
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movq %rdx, %rsi # rsi <- Source
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movq %rcx, %rdi # rdi <- Destination
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leaq -1(%rsi, %r8,), %r9 # r9 <- Last byte of Source
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cmpq %rdi, %rsi
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movq %rdi, %rax # rax <- Destination as return value
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jae L0 # Copy forward if Source > Destination
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cmpq %rdi, %r9 # Overlapped?
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jae L_CopyBackward # Copy backward if overlapped
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L0:
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xorq %rcx, %rcx
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subq %rdi, %rcx # rcx <- -rdi
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andq $15, %rcx # rcx + rsi should be 16 bytes aligned
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jz L1 # skip if rcx == 0
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cmpq %r8, %rcx
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cmova %r8, %rcx
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subq %rcx, %r8
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rep movsb
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L1:
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movq %r8, %rcx
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andq $15, %r8
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shrq $4, %rcx # rcx <- # of DQwords to copy
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jz L_CopyBytes
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movdqa %xmm0, 0x18(%rsp) # save xmm0 on stack
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L2:
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movdqu (%rsi), %xmm0 # rsi may not be 16-byte aligned
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movntdq %xmm0, (%rdi) # rdi should be 16-byte aligned
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addq $16, %rsi
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addq $16, %rdi
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loop L2
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mfence
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movdqa 0x18(%rsp), %xmm0 # restore xmm0
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jmp L_CopyBytes # copy remaining bytes
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L_CopyBackward:
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movq %r9, %rsi # rsi <- Last byte of Source
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leaq -1(%rdi, %r8,), %rdi # rdi <- Last byte of Destination
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std
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L_CopyBytes:
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movq %r8, %rcx
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rep movsb
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cld
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popq %rdi
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popq %rsi
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ret
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